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emphasizedparser: Underscore does not need backslash

Signed-off-by: Patrick José Pereira <patrickelectric@gmail.com>
Šī revīzija ir iekļauta:
Patrick José Pereira 2018-10-25 14:47:52 -03:00
vecāks 7c26aa0431
revīzija a84da9de61

Parādīt failu

@ -41,7 +41,7 @@ public:
void
Parse(std::string& line) override
{
static std::regex re("(?!.*`.*|.*<code>.*)\\_(?!.*`.*|.*<\\/code>.*)([^\\_]*)\\_(?!.*`.*|.*<\\/code>.*)");
static std::regex re("(?!.*`.*|.*<code>.*)_(?!.*`.*|.*<\\/code>.*)([^_]*)_(?!.*`.*|.*<\\/code>.*)");
static std::string replacement = "<em>$1</em>";
line = std::regex_replace(line, re, replacement);