shared: sqlitesearch: Remove subquery for content search
The subquery only works for boolean retrieval, its ordering is irrelevant. Thus, use INNER JOIN instead and order by rank by default.
Este cometimento está contido em:
ascendente
e225fdad21
cometimento
ee4fe51a77
@ -125,6 +125,7 @@ QPair<QString, QVector<QString>> SqliteSearch::createSql(const Token &token)
|
||||
QSqlQuery SqliteSearch::makeSqlQuery(const QSSQuery &query)
|
||||
{
|
||||
QString whereSql;
|
||||
QString joinSql;
|
||||
QVector<QString> bindValues;
|
||||
bool isContentSearch = query.getTokensMask() & FILTER_CONTENT == FILTER_CONTENT;
|
||||
if(query.getTokens().isEmpty())
|
||||
@ -134,19 +135,32 @@ QSqlQuery SqliteSearch::makeSqlQuery(const QSSQuery &query)
|
||||
|
||||
for(const Token &token : query.getTokens())
|
||||
{
|
||||
auto sql = createSql(token);
|
||||
whereSql += sql.first;
|
||||
bindValues.append(sql.second);
|
||||
if(token.type == FILTER_CONTENT_CONTAINS)
|
||||
{
|
||||
joinSql += " INNER JOIN content_fts ON content.id = content_fts.ROWID ";
|
||||
whereSql += " content_fts.content MATCH ? ";
|
||||
bindValues.append(token.value);
|
||||
}
|
||||
else
|
||||
{
|
||||
auto sql = createSql(token);
|
||||
whereSql += sql.first;
|
||||
bindValues.append(sql.second);
|
||||
}
|
||||
}
|
||||
|
||||
QString prepSql;
|
||||
QString sortSql = createSortSql(query.getSortConditions());
|
||||
if(isContentSearch)
|
||||
{
|
||||
if(sortSql.isEmpty())
|
||||
{
|
||||
sortSql = "ORDER BY rank";
|
||||
}
|
||||
prepSql =
|
||||
"SELECT file.path AS path, group_concat(content.page) AS pages, file.mtime AS mtime, file.size AS size, "
|
||||
"file.filetype AS filetype FROM file INNER JOIN content ON file.id = content.fileid WHERE 1=1 AND " +
|
||||
whereSql + " GROUP BY file.path " + sortSql;
|
||||
"file.filetype AS filetype FROM file INNER JOIN content ON file.id = content.fileid " +
|
||||
joinSql + " WHERE 1=1 AND " + whereSql + " GROUP BY file.path " + sortSql;
|
||||
}
|
||||
else
|
||||
{
|
||||
|
Carregando…
Criar uma nova questão referindo esta
Bloquear um utilizador